1/2x(x+3)(2x-5)=20^2

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Solution for 1/2x(x+3)(2x-5)=20^2 equation: 



1/2x(x+3)(2x-5)=20^2

We move all terms to the left:

1/2x(x+3)(2x-5)-(20^2)=0



Domain of the equation: 2x(x+3)(2x-5)!=0

x∈R



We add all the numbers together, and all the variables

1/2x(x+3)(2x-5)-400=0

We multiply parentheses ..

1/2x(+2x^2-5x+6x-15)-400=0

We multiply all the terms by the denominator


-400*2x(+2x^2-5x+6x-15)+1=0

Wy multiply elements

-800x(++1=0

We use the square of the difference formula

-800x(+1=0

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